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DANGER: Non-isolated circuit. Risk of electric shock.
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About

A capacitive power supply uses the reactance of a capacitor to reduce mains voltage for low-current applications (e.g., LED drivers, IoT sensors). Unlike resistive droppers, capacitors do not dissipate active power as heat, making them efficient. However, the circuit is non-isolated, meaning the output is directly connected to the mains. This poses a severe shock hazard.

This calculator determines the required series capacitance based on the desired load current and output voltage. It uses the vector relationship between voltages, as the capacitor voltage is 90 degrees out of phase with the resistive load voltage.

electronics power supply capacitor reactance circuit

Formulas

The capacitive reactance Xc depends on frequency f and capacitance C:

Xc = 12πfC

Since the capacitor voltage Vc and load voltage Vout are in quadrature:

Vc = Vin2 Vout2

The required capacitance is:

C = I2πfVc

Reference Data

Capacitor (X-Cap)Value (μF)Reactance @ 50HzReactance @ 60HzMax Current (approx 230V)
1040.1 μF31.8 kΩ26.5 kΩ~7 mA
2240.22 μF14.5 kΩ12.0 kΩ~15 mA
3340.33 μF9.6 kΩ8.0 kΩ~23 mA
4740.47 μF6.8 kΩ5.6 kΩ~33 mA
6840.68 μF4.7 kΩ3.9 kΩ~48 mA
1051.0 μF3.2 kΩ2.6 kΩ~70 mA

Frequently Asked Questions

A bleed resistor (parallel to C) discharges the capacitor when unplugged to prevent shocks. A surge resistor (series) limits inrush current when the device is plugged in at peak mains voltage.
No. You MUST use "X-rated" (X2) safety capacitors designed to withstand mains voltage surges and fail open (not short) to prevent fire.
Capacitive droppers are practical only for currents under 100mA. Higher currents require large, expensive capacitors, making switching power supplies a better choice.