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m
kN/m
kN
GPa
MPa
m
m
×10−6 m4
Enter beam parameters and press Calculate to see results.
Reaction RA โ€”
Reaction RB โ€”
Max Shear Force Vmax โ€”
Max Bending Moment Mmax โ€”
Max Deflection δmax โ€”
Second Moment of Area I โ€”
Max Bending Stress σmax โ€”
Safety Factor โ€”
Deflection Ratio L/δ โ€”
Failure Marginal Safe
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About

Incorrect beam sizing causes structural failure. A floor joist undersized by 10% in moment of inertia I can exceed allowable deflection limits under service loads, leading to cracked finishes, bouncy floors, or collapse. This calculator applies Euler-Bernoulli beam theory to compute reaction forces, maximum bending moment M, shear force V, deflection ฮด, and bending stress ฯƒ for simply supported and cantilever beams under point or uniformly distributed loads. Results assume linear-elastic material behavior and small deflections relative to span length.

The tool checks computed bending stress against material yield strength ฯƒy and reports a safety factor. A safety factor below 1.0 indicates the beam will yield under the applied load. Most building codes require a minimum factor of 1.5 to 2.0 for static loads. Note: this tool does not account for lateral-torsional buckling, dynamic loads, or connection detailing. For critical structural members, verify results with a licensed engineer.

beam calculator bending moment shear force deflection structural engineering beam stress euler-bernoulli cantilever beam simply supported beam

Formulas

Bending stress at the extreme fiber of a beam cross-section under pure bending (the flexure formula):

ฯƒ = M โ‹… yI

where ฯƒ = bending stress Pa, M = bending moment Nโ‹…m, y = distance from neutral axis to extreme fiber m, I = second moment of area m4.

Maximum bending moment for a simply supported beam with uniformly distributed load w:

Mmax = w โ‹… L28

Maximum deflection for a simply supported beam with uniformly distributed load:

ฮดmax = 5 โ‹… w โ‹… L4384 โ‹… E โ‹… I

Maximum bending moment for a cantilever beam with uniformly distributed load:

Mmax = w โ‹… L22

Maximum deflection for a cantilever beam with uniformly distributed load:

ฮดmax = w โ‹… L48 โ‹… E โ‹… I

For a simply supported beam with a point load P at midspan: Mmax = P โ‹… L4 and ฮดmax = P โ‹… L348 โ‹… E โ‹… I. For a cantilever with point load at free end: Mmax = P โ‹… L and ฮดmax = P โ‹… L33 โ‹… E โ‹… I.

Safety factor: SF = ฯƒyฯƒmax, where ฯƒy is the material yield strength and ฯƒmax is the maximum computed bending stress.

Reference Data

MaterialElastic Modulus E GPaYield Strength ฯƒy MPaDensity kg/m3Typical Use
Structural Steel (A36)2002507850I-beams, columns, frames
Structural Steel (A992)2003457850Wide-flange beams (W-shapes)
Stainless Steel (304)1932158000Corrosion-resistant structures
Aluminum 6061-T668.92762700Lightweight frames, aerospace
Aluminum 2024-T473.13242780Aircraft structures
Titanium Ti-6Al-4V113.88804430Aerospace, medical implants
Cast Iron (Gray)1001307200Machine bases, pipe fittings
Copper C11000117698940Electrical conductors
Douglas Fir (No.1)12.435530Joists, rafters, residential
Southern Pine (No.1)13.138570Treated lumber, decking
Spruce-Pine-Fir (SPF)9.527420Light framing, studs
Glulam (24F-V4)12.441500Long-span timber beams
LVL (Laminated Veneer)13.844580Headers, ridge beams
Concrete (f'c 25 MPa)25252400Reinforced beams, slabs
Concrete (f'c 40 MPa)31.6402400High-strength columns, precast
GFRP (Glass Fiber RP)404501900Corrosive environments, bridges
CFRP (Carbon Fiber RP)15015001600Aerospace, high-performance
Brass (C36000)971248500Fittings, hardware
Bronze (C93200)1031258800Bearings, marine hardware
Magnesium AZ31B452001770Ultralight structures

Frequently Asked Questions

Deflection is proportional to span length raised to the 4th power (Lโด) for distributed loads. Doubling the span increases deflection by a factor of 16 if all else remains equal. Most building codes limit deflection to L/360 for floor beams under live load and L/240 for total load. If your computed deflection exceeds these limits, increase the moment of inertia I by selecting a deeper cross-section rather than a wider one - depth contributes cubically to I for rectangular sections.
Elastic modulus E (in GPa) measures material stiffness - how much the beam resists deformation. Yield strength ฯƒ_y (in MPa) is the stress at which permanent deformation begins. A beam can have adequate stiffness (low deflection) but still fail if bending stress exceeds ฯƒ_y. Conversely, a very strong material with low E (like some polymers) may deflect excessively. Both must be checked: deflection against serviceability limits, and stress against strength limits with an appropriate safety factor.
The second moment of area I for a rectangle equals bยทhยณ/12, where b is width and h is height (depth). This is the most common cross-section for timber beams and a useful baseline for any material. For I-beams (W-shapes), I is significantly larger per unit weight because material is concentrated at the flanges. If you are using a standard steel W-shape, input the published I value directly from the AISC Steel Manual rather than computing from b and h.
A safety factor of 1.5 assumes static, well-characterized loading on ductile material with consistent quality. Increase to 2.0-3.0 for dynamic or impact loads (machinery, vehicles), brittle materials (cast iron, concrete in tension), uncertain loading conditions, or when failure consequences are severe (public structures). Timber beams require higher factors (2.0+) due to natural variability in grain structure, moisture content, and knots.
No. The Euler-Bernoulli beam theory used here considers bending deflection only, which dominates for slender beams (span-to-depth ratio > 10). For deep beams (ratio < 5), shear deflection becomes significant and Timoshenko beam theory should be applied instead. For typical structural beams in buildings (ratio 12-24), bending deflection accounts for over 95% of total deflection, so the results here are reliable.
This calculator places the point load at midspan, which produces the maximum bending moment for a simply supported beam. For an off-center load at distance a from the left support, M_max = Pยทaยท(Lโˆ’a)/L at the load point, and the maximum deflection shifts toward the longer segment. If your load is off-center, the midspan results here are conservative (they overestimate M_max), which errs on the safe side.
No. Continuous beams over multiple supports develop negative moments at interior supports and require solving indeterminate structural equations (moment distribution, stiffness method, or finite element analysis). This tool handles single-span determinate beams only: simply supported (two supports at ends) and cantilever (one fixed end, one free end).