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Category Electronics
Total circuit current draw
Total load wattage at 24V
Wire run from source to load (not round-trip)
Nominal DC voltage (default 24V)
3%
NEC recommends ≤3% for branch circuits

Enter values and press Calculate to see results

Recommended AWG
Voltage Drop
Drop Percentage
Voltage at Load
Current
Derated Ampacity
Wire Diameter
Wire Area
Power Loss in Wire
AWGV-DropDrop %AmpacityStatus
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About

Low-voltage 24V DC systems are unforgiving. A wire gauge that works at 120V AC fails catastrophically at 24V because the same current produces the same resistive loss, but that loss now represents a far larger fraction of your supply voltage. A 3% drop at 120V is 3.6V. At 24V, it is 0.72V - which demands conductor cross-sections roughly five times larger for the same load and distance. Undersized wire causes dimming LEDs, malfunctioning controllers, solenoid chatter, and in worst cases, insulation melt and fire. This calculator sizes conductors using NEC Chapter 9 Table 8 resistance values and ampacity tables from NEC 310.15, checking both voltage drop and current-carrying capacity to return the smallest compliant AWG gauge.

This tool approximates conditions for standard insulation types (THHN/THWN) in dry locations. For wet, underground, or high-ambient-temperature environments, apply additional derating factors per NEC 310.15(B). Results assume a two-conductor circuit (supply and return). Pro tip: always round up one gauge from the calculated minimum when runs exceed 50ft - real-world connections, splices, and terminal resistance add loss the formula does not capture.

wire size calculator 24 volt wire gauge voltage drop calculator AWG calculator low voltage wiring DC wire sizing NEC wire size

Formulas

The calculator determines wire size by computing the voltage drop across a two-conductor run and comparing it against the user-specified maximum allowable drop. It simultaneously checks that the chosen gauge can safely carry the required current (ampacity).

Vdrop = 2 × L × I × R1000

Where Vdrop = voltage lost in conductors V, L = one-way wire length ft, I = circuit current A, R = conductor resistance per 1000ft at rated temperature Ω/kft. The factor 2 accounts for the round-trip (supply + return conductors).

Vdrop% = VdropVsource × 100

If current is unknown but wattage is given, current is derived from power:

I = PV

Where P = power in W and V = 24V. The algorithm iterates AWG sizes from 18 to 4/0, selects the smallest gauge where Vdrop% tolerance AND I ampacity.

Reference Data

AWGDiameter mmArea mm²Area kcmilCu Resistance Ω/1000ft @75°CAl Resistance Ω/1000ft @75°CCu Ampacity A (THHN 90°C)Al Ampacity A (THHN 90°C)Typical 24V Use
181.0240.8231.627.7712.814 - Thermostats, doorbells
161.2911.3092.584.898.0518 - LED strips, sensors
141.6282.0814.113.075.0625 - Small solenoids, relays
122.0533.3096.531.933.183025Solar charge controllers
102.5885.26110.381.212.004035Bilge pumps, trolling motors
83.2648.36616.510.7641.265545Winches, large pumps
64.11513.3026.240.4910.8087560Inverter feed lines
45.18921.1541.740.3080.5089575Battery bank connections
35.82726.6752.620.2450.40311585High-current DC distribution
26.54433.6266.360.1940.319130100Large inverters, solar arrays
17.34842.4183.690.1540.253150115High-power DC motors
1/08.25253.49105.60.1220.201170135Battery-to-inverter runs
2/09.26667.43133.10.09670.159195150Large solar systems
3/010.40485.03167.80.07660.126225175Commercial DC bus bars
4/011.684107.2211.60.06080.100260205Main battery cables, EV systems

Frequently Asked Questions

Voltage drop is proportional to current, not voltage. A 100W load draws 4.17A at 24V versus 0.83A at 120V - five times the current. The resistive loss (Vdrop = I × R) scales linearly with current, and that loss is a larger percentage of the lower source voltage. You need approximately 5× the conductor cross-sectional area to maintain the same percentage voltage drop.
NEC recommends no more than 3% for branch circuits and 5% total (feeder plus branch). For sensitive electronics (PLCs, LED drivers, communication equipment), many engineers design to 2% or less. At 24V, a 3% drop is only 0.72V - many devices have a minimum operating voltage of 22V, leaving very little margin.
Higher ambient temperatures reduce insulation ampacity. NEC 310.15(B)(1) provides correction factors: at 40°C ambient (vs. the 30°C base), THHN-rated copper ampacity drops by about 12%. At 50°C, the derating factor is 0.82, meaning a wire rated for 30A can only safely carry 24.6A. Additionally, resistance increases with temperature, worsening voltage drop. This calculator applies the NEC temperature correction factor to ampacity.
Copper is standard for low-voltage DC because its resistivity (10.4 Ω⋅cmil/ft) is about 61% that of aluminum (17.0 Ω⋅cmil/ft). Aluminum requires roughly 1.6× the cross-sectional area for equivalent performance, typically bumping up two AWG sizes. Aluminum is viable for long runs above 4 AWG where cost savings outweigh the size increase, but requires anti-oxidant compound and rated connectors to prevent galvanic corrosion at terminations.
The factor of 2 accounts for the round-trip current path - out on the positive conductor and back on the negative (or ground return). This applies to standard two-wire DC circuits. For systems with a chassis/hull ground return (common in marine and automotive), use a factor of 1 for the grounded conductor if the chassis impedance is negligible. However, this is not recommended for permanent installations due to corrosion risk and unreliable ground paths.
NEC 310.15(C)(1) requires ampacity derating when more than 3 current-carrying conductors occupy a single raceway. For 4 - 6 conductors, derate to 80%. For 7 - 9, derate to 70%. This calculator provides conduit fill adjustment. The derating stacks with temperature correction - multiply both factors against the base ampacity to find the effective current limit.